5x/(3x^2)+2x=0

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Solution for 5x/(3x^2)+2x=0 equation: 


D( x )

3*x^2 = 0

3*x^2 = 0

3*x^2 = 0

3*x^2 = 0 // : 3

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+(5*x)/(3*x^2) = 0

2*x^1+5/3*x^-1 = 0

(2*x^2+5/3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+5/3*x^0) = 0

x^1

2*x^2+5/3 = 0

2*x^2+5/3 = 0

DELTA = 0^2-(2*4*(5/3))

DELTA = -40/3

DELTA < 0

x in { } 

x belongs to the empty set

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